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Possible issue. #2

@DmytroHubernatorov

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@DmytroHubernatorov

f = open('{}{}.txt'.format(workflow_name, i), 'w')

In case of intensive usage it will not guarantee file name will be 'engaged' by another process.
There are functions for unique file name creation.
Or update implementation like - try to create file name and grab it.

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